Which of the following carboxylic acids could | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Only chiral compounds can be resolved into their enantiomers using an enantiomerically pure chiral resolving agent. $(A)$ $1,5-$dinitro-naphthalen

Vedclass · Accepted Answer

$6$,$6$'-dinitro-biphenyl-$2$,$2$'-dicarboxylic acid

Vedclass · Answer

(C) Only chiral compounds can be resolved into their enantiomers using an enantiomerically pure chiral resolving agent. $(A)$ $1,5-$dinitro-naphthalene$-2,6-$dicarboxylic acid is achiral due to the presence of a plane of symmetry. $(B)$ $2,5-$dinitro-terephthalic acid is achiral due to the presence of a plane of symmetry. $(C)$ $6$,$6$'-dinitro-biphenyl-$2$,$2$'-dicarboxylic acid exhibits atropisomerism due to restricted rotation around the single bond connecting the two phenyl rings,caused by the bulky ortho-substituents. This makes the molecule chiral and resolvable. $(D)$ $8-$nitro-anthracene$-1-$carboxylic acid is planar and achiral. Therefore,the correct option is $(C)$.

Which of the following carboxylic acids could be resolved by reaction with an enantiomerically pure chiral amine?

Similar Questions

Arrange the following compounds in the increasing order of their $pK_a$ values:
$I.$ Phenol
$II.$ $p$-Nitrophenol
$III.$ Ethanol
$IV.$ $p$-Nitrobenzoic acid

At which value of $n$ does the formation of a six-membered ring take place in the following reaction?
$Br-(CH_2)_n-CH_2-Br + CH_2(CO_2Et)_2 \xrightarrow{NaOEt, EtOH} \text{cyclic product}$

Hydrolysis of an ester gives a carboxylic acid which on Kolbe's electrolysis yields ethane. The ester is

In the following reactions,what are $B$ and $X$ respectively?
$C_2H_5MgBr$ $\xrightarrow{ClCN} C_2H_5CN$ $\xrightarrow{H_3O^+} B$
$CH_3COCH_3$ $\xrightarrow[NaOH]{I_2} X + CHI_3$ $\xrightarrow{Ag} Y$
$C_6H_5NH_2$ $\xrightarrow[HCl]{NaNO_2} P$ $\xrightarrow{CuCN} Q$ $\xrightarrow{+4H} R$

Assertion: Acetamide has a more polar $C=O$ group than ethyl acetoacetate.
Reason: $-\ddot{N}H_{2}$ is more electron-donating than $-\ddot{O}C_{2}H_{5}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module